It is official and first in the history moment. IITs have declared the cut-off for recently held IIT JEE examination. IIT has officially revealed the minimum qualifying marks in each of the subjects and the aggregate cut-off marks required for being included in the all India ranking.
General Category students will have to score 10% in each of the subjects, OBC Category students need 9% marks in each of the subjects, and SC/ST/PD students will need 5% minimum marks in each of the subjects. Apart from clearing the minimum cut-off in each subject, students also need to meet the qualifying aggregate marks too. The aggregate cut-off required by General Category candidates is 35%, for OBC 31.5%, and for SC/ST/PD students 17.5%.
|Category||Cut-Off Maths||Cut-Off Chemistry||Cut-Off Physics||Cut-Off Total|
As reported by Hindustan Times, this decision of revealing the cut-off is an after-effect of the Supreme Court’s observations in a case filed by IIT Kharagpur professor Rajiv Kumar, who filed petitions to bring transparency into the IIT-JEE examination system.
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