It is official and first in the history moment. IITs have declared the cut-off for recently held IIT JEE examination. IIT has officially revealed the minimum qualifying marks in each of the subjects and the aggregate cut-off marks required for being included in the all India ranking.
General Category students will have to score 10% in each of the subjects, OBC Category students need 9% marks in each of the subjects, and SC/ST/PD students will need 5% minimum marks in each of the subjects. Apart from clearing the minimum cut-off in each subject, students also need to meet the qualifying aggregate marks too. The aggregate cut-off required by General Category candidates is 35%, for OBC 31.5%, and for SC/ST/PD students 17.5%.
|Category||Cut-Off Maths||Cut-Off Chemistry||Cut-Off Physics||Cut-Off Total|
As reported by Hindustan Times, this decision of revealing the cut-off is an after-effect of the Supreme Court’s observations in a case filed by IIT Kharagpur professor Rajiv Kumar, who filed petitions to bring transparency into the IIT-JEE examination system.
Incoming search terms:
- iit cut off 2012
- iit 2012 cutoff
- iit jee 2012 cutoff marks for obc
- iit jee 2012 cutoff
- cut off marks for iit jee 2012 for obc
- iit jee 2012 cutoff marks for sc
- jee 2012 cut off marks
- iit jee cut off 2012
- iit jee 2012 obc cut off marks
- jee 2012 cutoff marks
- iit cut off marks 2012 for sc
- iit cutoff 2012
- Jee main 2012 cut off
- jee main cut off 2012
- jee main cutoff marks 2012